Question

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In the given figure, AOB is a straignt line, ∠AOC = (13x − 8)°, ∠COD = 50° and ∠BOD = (x + 10)°. The value of x is



(a) 32
(b) 42
(c) 36
(d) 52

Answer 1

$$\begin{gathered} \left(a\right)32 \\ \begin{array}{l}\text{(3}x-8)°+(x+10)°+50°=180°(\mathrm{linear}\mathrm{pair})\\ \text{=>4}x°+52°=180°\\ \text{=>4}x°=128°\\ \text{=>}x°=32°\\ \end{array} \\ \therefore x=32 \end{gathered}$$