Question

Mark (✓) against the correct answer
In the given figure, PQ || RS. ∠PAB = 60° and ∠ACS = 100°.
Then ∠BAC = ?



(a) 40°
(b) 60°
(c) 80°
(d) 50°

Answer 1

$$\begin{gathered} \left(\mathrm{a}\right)40° \\ \begin{array}{l}\angle \text{PAC}=\angle \text{ACS}={100}^0\left[\text{alternate angles}\right]\\ \angle \text{PAB}+\angle \text{BAC}={100}^0\\ =>\angle \text{BAC}=100°-60°=40°\end{array} \end{gathered}$$