Mark the correct alternative in each of the following-If 24-125-24- A 10- B 100- C 1000- then A- B - C isa 3b 6c 13d 8

24.125=24+0.125=24+0.1+0.02+0.005=24+110+2100+51000 Comparing this with the given expression, we get A = 1, B = 2 and C = 5 there4; nbsp;A + B + C = 1 ...

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Standard VI

Mathematics

Addition and Subtraction of Decimals

Mark the corr...

Question

Mark the correct alternative in each of the following:

If $24.125 = 24 + \frac{A}{10} + \frac{B}{100} + \frac{C}{1000}$ , then A + B + C is

(a) 3 (b) 6 (c) 13 (d) 8

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Solution

$24.125 = 24 + 0.125 = 24 + 0.1 + 0.02 + 0.005 = 24 + \frac{1}{10} + \frac{2}{100} + \frac{5}{1000}$

Comparing this with the given expression, we get

A = 1, B = 2 and C = 5

∴ A + B + C = 1 + 2 + 5 = 8

Hence, the correct answer is option (d).

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Mark the correct alternative in each of the following: If 24.125=24+A10+B100+C1000, then A + B + C is (a) 3 (b) 6 (c) 13 (d) 8

24.125=24+0.125=24+0.1+0.02+0.005=24+110+2100+51000 Comparing this with the given expression, we get A = 1, B = 2 and C = 5 ∴ A + B + C = 1 + 2 + 5 = 8 Hence, the correct answer is option (d).

Mark the correct alternative in each of the following:

If $24.125 = 24 + \frac{A}{10} + \frac{B}{100} + \frac{C}{1000}$ , then A + B + C is

(a) 3 (b) 6 (c) 13 (d) 8

$24.125 = 24 + 0.125 = 24 + 0.1 + 0.02 + 0.005 = 24 + \frac{1}{10} + \frac{2}{100} + \frac{5}{1000}$

Comparing this with the given expression, we get

A = 1, B = 2 and C = 5

∴ A + B + C = 1 + 2 + 5 = 8

Hence, the correct answer is option (d).