wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Mark the correct alternative in each of the following:

If y=x+1x, then dydx at x = 1 is

(a) 1 (b) 12 (c) 12 (d) 0

Open in App
Solution


y=x+1x =x12+x-12

Differentiating both sides with respect to x, we get

dydx=ddxx12+x-12 =ddxx12+ddxx-12 =12x12-1+-12x-12-1 y=xndydx=nxn-1 =12x-12-12x-32

Putting x = 1, we get

dydxx=1=12×1-12×1=0

Thus, dydx at x = 1 is 0.

Hence, the correct answer is option (d).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Theorem of Calculus
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon