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Question

Mark the correct alternative in each of the following :

In any ΔABC, a2(sin Bsin C)=


A

a2+b2+c2

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B

a2

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C

b2

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D

0

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Solution

The correct option is D

0


Let a2 sinB=b2 sin A, b2 sin C=c2 sin Aa2 sin C=c2 sin Aa2 (sin Bsin C)=a2 (sin Bsin C)+b2 (sin Csin A)+c2 (sin Asin B)=a2 sin Ba2 sin C+b2 sin Cb2 sin A+c2 sin Ac2 sin B=b2 sin Aa2 sin C+b2 sin Cb2 sin A+a2 sin Cb2 sin C=0


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