Mark the correct alternative in each of the following :
In any ΔABC, the value of 2ac sin(A−B+C2) is
a2+b2−c2
c2+a2−b2
b2−c2−a2
c2−a2−b2
In ΔABCA+B+C2−B=π2−B⇒ A+C−B2=π2−B∴ 2ac sin 12(A−B+C)=2ac sin(π2−B)=2ac cos B=2ac.a2+c2−b22ac=a2+c2−b2
In any ΔABC, 2(bc cos A+ca cos B+ab cos C)=
In a △ABC,2casin(A−B+C2) is equal to