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Question

Mark the correct alternative in each of the following :

In any ΔABC, the value of 2ac sin(AB+C2) is


A

a2+b2c2

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B

c2+a2b2

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C

b2c2a2

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D

c2a2b2

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Solution

The correct option is B

c2+a2b2


In ΔABCA+B+C2B=π2B A+CB2=π2B 2ac sin 12(AB+C)=2ac sin(π2B)=2ac cos B=2ac.a2+c2b22ac=a2+c2b2


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