Mark the correct alternative in each of the following :
L is a variable line such that the algebraic sum of the distance of the points (1, 1), (2, 0) and (0, 2) from the line is equal to zero. The line L will always pass through
(1, 1)
Let ax+by+c=0 be tje variable line. It is that the algebraic sum of the distances of the points (1, 1), (2, 0) and (0, 2) from the line is equal to zero.
∴ a+b+c√a2+b2+2a+0+c√a2+b2+0+2b+c√a2+b2=0
⇒ 3a+3b+3c=0
⇒ a+b+c=0
Substituting c=−a−b in ax+by+c=0, we get :
ax+by−a−b=0
⇒ a(x−1)+b(y−1)=0
⇒ (x−1)+ba(y−1)=0
This line is of the form L1+λL2=0, which passes through the intersection of L1=0 and L2=0, i.e. x−1=0 and y−1=0 \
⇒ x=1, y=1