Mark the correct alternative in each of the following-Reciprocal of -34 isa 34b 43c -43d None of these

We know that the reciprocal of the rational number ab is ab 1=ba. there4; Reciprocal of 34 = 34 1=4 3=4 #215; 1 3 #215; 1= 43 Hence, the correct an ...

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Standard VIII

Mathematics

Negation of a Number

Mark the corr...

Question

Mark the correct alternative in each of the following:

Reciprocal of $\frac{- 3}{4}$ is

(a) $\frac{3}{4}$ (b) $\frac{4}{3}$ (c) $\frac{- 4}{3}$ (d) None of these

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Solution

We know that the reciprocal of the rational number $\frac{a}{b}$ is ${(\frac{a}{b})}^{- 1} = \frac{b}{a}$ .

∴ Reciprocal of $\frac{- 3}{4}$

$= {(\frac{- 3}{4})}^{- 1} = \frac{4}{- 3} = \frac{4 \times (- 1)}{- 3 \times (- 1)} = \frac{- 4}{3}$

Hence, the correct answer is option (c).

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Similar questions

Q. Mark (✓) against the correct answer
The multiplicative inverse of

\frac{- 3}{4}

is
(a)

\frac{3}{4}

(b)

\frac{4}{3}

(c)

\frac{- 4}{3}

(d) none of these

Q. Mark the correct alternative in each of the following:

If

\frac{x}{2} + \frac{1}{3} = 1

, then x =

(a)

\frac{3}{4}

(b)

\frac{4}{3}

(c)

- \frac{3}{4}

(d)

\frac{- 4}{3}

Q. If sin (π cos θ) = cos (π sin θ), then sin 2 θ =

(a)

\pm \frac{3}{4}

(b)

\pm \frac{4}{3}

(c)

\pm \frac{1}{3}

(d) none of these

Q. If sin (π cos x) = cos (π sin x), then sin 2 x =

(a)

\pm \frac{3}{4}

(b)

\pm \frac{4}{3}

(c)

\pm \frac{1}{3}

(d) none of these

Q. Mark the correct alternative in each of the following:

- \frac{102}{119}

in standard form is

(a)

- \frac{6}{7}

(b)

\frac{6}{7}

(c)

- \frac{6}{17}

(d) None of these

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Mark the correct alternative in each of the following: Reciprocal of -34 is (a) 34 (b) 43 (c) -43 (d) None of these

We know that the reciprocal of the rational number ab is ab-1=ba. ∴ Reciprocal of -34 =-34-1=4-3=4×-1-3×-1=-43 Hence, the correct answer is option (c).

Mark the correct alternative in each of the following:

Reciprocal of $\frac{- 3}{4}$ is

(a) $\frac{3}{4}$ (b) $\frac{4}{3}$ (c) $\frac{- 4}{3}$ (d) None of these

We know that the reciprocal of the rational number $\frac{a}{b}$ is ${(\frac{a}{b})}^{- 1} = \frac{b}{a}$ .

∴ Reciprocal of $\frac{- 3}{4}$

$= {(\frac{- 3}{4})}^{- 1} = \frac{4}{- 3} = \frac{4 \times (- 1)}{- 3 \times (- 1)} = \frac{- 4}{3}$

Hence, the correct answer is option (c).