Question

Mark the correct alternative in each of the following:

The probability that a number selected at random from the numbers 1, 2, 3, ..., 15 is a multiple of 4, is

(a) $\frac{4}{15}$ (b) $\frac{2}{15}$ (c) $\frac{1}{5}$ (d) $\frac{1}{3}$ [CBSE 2014]

Answer 1

The total number of given numbers is 15.

∴ Total number of outcomes = 15

Among the given numbers, the multiples of 4 are 4, 8 and 12.

So, the favourable number of outcomes are 3.

∴ P(number selected is a multiple of 4) = $\frac{\mathrm{Favourable}\mathrm{number}\mathrm{of}\mathrm{outcomes}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{outcomes}}=\frac{3}{15}=\frac{1}{5}$

Hence, the correct answer is option C.