Mark the correct alternative in the following question-How much is -2 x2-x-1 less than x2-2 x-3 -a -x2-3 x-2b 3 x2-x-4c -3 x2-x-4d 3 x2-3 x-4

Since, (x2 nbsp;+ 2x nbsp; nbsp;3) nbsp; nbsp;( 2x2 nbsp;+ nbsp;x nbsp;+ 1) = nbsp;x2 nbsp;+ 2x nbsp; nbsp;3 + nbsp;2x2 nbsp; ...

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Addition and Subtraction of Algebraic Expressions

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Question

Mark the correct alternative in the following question:

How much is $-$ 2x² + x + 1 less than x² + 2x $-$ 3?

(a) $-$ x² + 3x $-$ 2 (b) 3x² + x $-$ 4 (c) $-$ 3x² $-$ x + 4 (d) 3x² + 3x $-$ 4

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Solution

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\frac{3 x^{2} + 2 x - 1}{x^{2} - x - 2} \times \frac{2 x^{2} - 3 x - 2}{3 x^{2} + 5 x - 2}

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(1 - 2 x + 3 x^{2})

4 + 3 x a n d 5 - 4 x + 2 x^{2}

3 x^{2} - 5 x a n d - x^{2} + 2 x + 5

\sqrt{3} x^{2} - 2 x + \frac{1}{2} = 0

x^{2} + \frac{1}{x^{2}} = 5

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x + \frac{1}{x} = 1

{(x + \frac{1}{x})}^{2} = 3 (x + \frac{1}{x}) + 4

x + \frac{1}{x} = x^{2}, x \neq 0

\begin{matrix} {lim}_{x \to 1} \frac{x^{2} - 3 x + 2}{x^{2} - 4 x + 3} {lim}_{x \to 2} \frac{x^{3} + x^{2} - 12}{x^{3} - x^{2} - x - 2} {lim}_{x \to \sqrt{2}} \frac{x^{2} + x \sqrt{2} - 4}{x^{2} - 3 x \sqrt{2} + 4} {lim}_{x \to 3} \frac{x^{3} - 3 x^{2} - x + 3}{x^{3} - 6 x^{2} + 9 x} \end{matrix}

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