Question

Mark the correct alternative in the following question:

The sum of the coefficients in the monomials 3a²b and $-$2ab² is

(a) 5 (b) $-$1 (c) 1 (d) 6

Answer 1

Since, the coefficient in the monomial 3a²b is 3 and the coefficient in the monomial $-$2ab² is $-$2.

So, the sum of the coefficients in the monomials 3a²b and $-$2ab² = 3 + ($-$2) = 3 $-$ 2 = 1

Hence, the correct alternative is option (c).