Mark the correct choice-Assertion A- The value of sin- cos 90- - - cos- sin- 90- - is equal to 1-Reason R- tan- - sec- 90- - -

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Properties of Determinants

Mark the corr...

Question

Mark the correct choice.
Assertion (A): The value of sin⁡θ cos (90°− θ) + cos⁡θ sin⁡ (90°− θ) is equal to 1.
Reason (R): tan⁡θ = sec⁡ (90° − θ)

Both A and R are true and R is not the correct explanation of A.

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Both A and R are true and R is the correct explanation of A.

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A is true but R is false.

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A is false but R is true.

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PT: cos(90 -θ) / 1+sin(90-θ) + 1+sin(90-θ)/cos(90-θ) = 2cosecθ

sinθ \cos (90 ° - θ) + \sin (90 ° - θ) cosθ = 1

\frac{sinθ}{\cos (90 ° - θ)} + \frac{cosθ}{\sin (90 ° - θ)} = 2

\frac{sinθ \cos (90 ° - θ) cosθ}{\sin (90 ° - θ)} + \frac{cosθ \sin (90 ° - θ) sinθ}{\cos (90 ° - θ)}

\frac{\cos (90 ° - θ) \sec (90 ° - θ) tanθ}{cosec (90 ° - θ) \sin (90 ° - θ) \cot (90 ° - θ)} + \frac{\tan (90 ° - θ)}{cotθ} = 2

\frac{\cos (90 ° - θ)}{1 + \sin (90 ° - θ)} + \frac{1 + \sin (90 ° - θ)}{\cos (90 ° - θ)} = 2 cosecθ

\frac{\sec (90 ° - θ) cosecθ - \tan (90 ° - θ) cotθ + \cos^{2} 25 ° + \cos^{2} 65 °}{3 \tan 27 ° \tan 63 °} = \frac{2}{3} \"[\"CBSE 2010\"]\"

cotθ \tan (90 ° - θ) - \sec (90 ° - θ) cosecθ + \sqrt{3} \tan 12 ° \tan 60 ° \tan 78 ° = 2 \"[\"CBSE 2010\"]\"

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