Question

Mark the correct option–

• A. $\text{(ii)}$ – Malic acid – $\text{5C}$
• B. $\text{(iii)}$ – Ketogulutaric acid – $\text{4C}$
• C. $\text{(ii)}$ – Malic acid – $\text{4C}$
• D. $\text{(i)}$ – Acetyl Co A – $\text{3C}$

Answer 1

The correct option is C $\text{(ii)}$ – Malic acid – $\text{4C}$

Below is the labelled diagram of citric acid cycle.


The above diagram shows that:-
- Malic acid – $4$ carbon
- $\alpha$- Ketoglutaric acid – $5$ carbon
- Acetyl coenzyme A – $2$ carbon
So, the correct answer is option 'c'.