Marks obtained by students in a class are given in the table. Find median

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Solution

Writing the distribution in tabulation form
$\frac{N}{2} = \frac{99}{2} = 49.5$
C.F. just above 49.5 is 52 whose corresponding variable value is 30.
$∴$ Required median = 30

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\begin{matrix} M a r k s & 20 & 15 & 17 & 30 & 22 & 25 o b t a i n e d F r e q u e n c y & 10 & 2 & 5 & 4 & 12 & 8 \end{matrix}

The following table shows the marks obtained by 6 students in a class. Find the average marks of the students in the class.

$\begin{matrix} M a r k s & F r e q u e n c y 78 & 2 65 & 1 85 & 2 74 & 1 \end{matrix}$

Obtained Marks	20-30	30-40	40-50	50-60	60-70	70-80
Number of students	5	9	8	12	13	3

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