CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Marks obtained in a test by X standard students of two sections A and B are given below:

Marks

No. of students in

Section A

No. of students in

Section B

25 – 30

30 – 35

35 – 40

40 – 45

45 – 50

5

10

25

8

2

5

12

20

8

5

Determine: (i) Which section’s performance is better? And (ii) Which section’s performance is more variable?

Open in App
Solution

Table of calculation for section A

Class Interval

(Rs)

Frequency

f

Mid-point

X

fX

Deviation

Square of Deviation D2

f.D2

25 – 30

5

27.5

137.5

– 9.2

84.64

423.2

30 – 35

10

32.5

325

– 4.2

17.64

176.4

35 – 40

25

37.5

937.5

0.8

0.64

16

40 – 45

8

42.5

340

5.8

33.64

269.12

45 – 50

2

47.5

95

10.8

116.64

233.28

= 50

1835

=1118

Sum of the frequencies = N = = 50

(i) Mean = = = 36.7

(ii) = = = 4.73

(iii) C.V = = = 12.90

Table of calculation for section B

Class Interval

(Rs)

Frequency

f

Mid-point

X

fX

Deviation

Square of Deviation D2

f.D2

25 – 30

5

27.5

137.5

–9.6

92.16

460.8

30 – 35

12

32.5

390

–4.6

21.16

253.92

35 – 40

20

37.5

750

0.4

0.16

3.2

40 – 45

8

42.5

340

5.4

29.16

233.28

45 – 50

5

47.5

237.5

10.4

108.16

540.8

= 50

= 1855

= 1492

Sum of the frequencies = N = = 50

(i) Mean = = = 37.1

(ii) == = 5.463

(iii) C.V= = = 14.73

The mean marks obtained by the students of section B is greater than that obtained by the students of section A.

Hence, section B’s performance is better.

The coefficient of variation for section B is more than that for section A.

Hence, the performance of section B is more variable.


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Step Deviation Method
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon