Question

Marks of the 100 students are distributed in the grouped frequency distribution.

Class marks (Marks)	150	160	170	180	190	200
No. of Students	24	14	16	11	21	14

Construct the histogram for the distribution given in the table.

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

As class marks or mid points are given, class intervals need to be calculated from the class marks.

Difference between the two successive classes = h = 160 - 150 =10.

If x is the class marks then, lower and upper boundary of every class is x - $\frac{h}{2}$ and x + $\frac{h}{2}$.

Hence, for the first group
lower boundary = 150 - $\frac{10}{2}$ = 145
upper boundary = 150 + $\frac{10}{2}$ = 155

Class interval is 145 - 155
Similarily,

Class marks	Class intervals	Frequency
150	145 - 155	24
160	155 - 165	14
170	165 - 175	16
180	175 - 185	11
190	185 - 195	21
200	195 - 205	14

Now make histogram with the help of above table.