Mars moving around sun covers A 1- A 2- A 3 areas in time t 1- t 2- t 3 t 1- t 2- t 3-1- 3- 5- then A 1- A 2- A 3 isA- 1- 1- 1B- 5- 3- 1C- 1- 9- 25D- 1- 3- 5

The correct option is D 1 : 3 : 5Kepler's second law A_1/t_1 =A_2/t_2 = A_3/t_3 (t_1 =x, t_2 = 3x ,t_3 =5x) A_1/1 = A_2/3 = A_3/5 A_1 : A_2 : A_3 = 1 : 3 : 5 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Kepler's Law

Mars moving a...

Question

Mars moving around sun covers $A_{1}, A_{2} & A_{3}$ areas in time $t_{1}, t_{2} & t_{3}$ . If $t_{1} : t_{2} : t_{3} = 1 : 3 : 5$ , then $A_{1} : A_{2} : A_{3}$ is

1 : 1 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 : 3 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 9 : 25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 3 : 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 1 : 3 : 5
Kepler's second law states that a planet sweeps out equal areas in equal times, that is, the area divided by time, called the areal velocity, is constant.
$\frac{A_{1}}{t_{1}} = \frac{A_{2}}{t_{2}} = \frac{A_{3}}{t_{3}} (t_{1} = x, t_{2} = 3 x, t_{3} = 5 x)$
$\frac{A_{1}}{1} = \frac{A_{2}}{3} = \frac{A_{3}}{5}$
$A_{1} : A_{2} : A_{3} = 1 : 3 : 5$ .

Suggest Corrections

Similar questions

If $a_{1} = \frac{1}{2 \times 5}, a_{2} = \frac{1}{5 \times 8}, a_{3} = \frac{1}{8 \times 11}, . . . . ., t h e n a_{1} + a_{2} + a_{3} + . . . . . + a_{100} i s$