Mason wishes to paint his room- If the dimensions of his walls are 11 ft- 8 ft and if there are 3 such walls- then find the area that Mason would have to paint-

Area of each wall = Length × Width Length = 11 ft Width = 8 ft ⇒Area of each wall = 11 × 8 = 88 sq ft Number of walls = 3 Thus, area of 3 walls = 3 × 88 = ...

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Standard VIII

Mathematics

Total Surface Area of a Cuboid

Mason wishes ...

Question

Mason wishes to paint his room. If the dimensions of his walls are $11 ft \times 8 ft$ and if there are 3 such walls, then find the area that Mason would have to paint.

264 sq ft

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96 sq ft

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88 sq ft

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216 sq ft

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Solution

The correct option is A 264 sq ft
$Area of each wall = L e n g t h \times W i d t h$

Length = 11 ft
Width = 8 ft

$\Rightarrow Area of each wall = 11 \times 8 = 88 s q f t$

Number of walls = 3

$Thus, area of 3 walls = 3 \times 88 = 264 s q f t$

Hence, Mason would have to paint a total area of 264 sq ft.

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Mason wishes to paint his room. If the dimensions of his walls are 11 ft×8 ft and if there are 3 such walls, then find the area that Mason would have to paint.

The correct option is A 264 sq ftArea of each wall = Length×Width Length = 11 ft Width = 8 ft ⇒Area of each wall = 11×8=88 sq ft Number of walls = 3 Thus, area of 3 walls = 3×88=264 sq ft Hence, Mason would have to paint a total area of 264 sq ft.

Mason wishes to paint his room. If the dimensions of his walls are $11 ft \times 8 ft$ and if there are 3 such walls, then find the area that Mason would have to paint.