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Byju's Answer

Standard XII

Physics

Com in Perfectly Inelastic Collision

Mass a hits b...

Question

Mass a hits b in elastically (e=0) while moving horizontally with some velocity along the common line of centres of the three equal masses each of same mass. Initially mass B and C are stationary and the spring is unstretched. Then which is incorrect.

compression will be maximum when blocks have same velocity

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velocity of C is maximum when (A+B) is at rest

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velocity of C is maximum when spring is undeformed

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velocity of C is minimum when spring is undeformed

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Solution

The correct option is A compression will be maximum when blocks have same velocity
$\begin{matrix} Correct option is (A) When A strikes B indastically (e = 0) then; Momentum = C P_{i} = P_{F} \begin{matrix} 2 m v = m V v = V / 2 Maximum compression will be maximum when both have same velocity as further there would be no direction for spring to move. \end{matrix} \end{matrix}$

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Mass a hits b in elastically (e=0) while moving horizontally with some velocity along the common line of centres of the three equal masses each of same mass. Initially mass B and C are stationary and the spring is unstretched. Then which is incorrect.

The correct option is A compression will be maximum when blocks have same velocity Correct option is (A) When A strikes B indastically (e=0) then; Momentum =CPi=PF2mv=mVv=V/2 Maximum compression will be maximum when both have same velocity as further there would be no direction for spring to move.