Mass density and radius of a solid sphere are ρ, R respectively. Gravitational field at an internal point which is at a distance r from the centre is.

\frac{4 πρGr}{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{4 {πρGr}^{2}}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4 πρG R^{3}}{3 r^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4 πρG R^{3}}{3 r}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{4 πρGr}{3}$
$E (r) = \frac{G M}{R^{3}} r f o r r \leq R = \frac{G}{R^{3}} (\frac{4}{3} π R^{3} . ρ r) = \frac{4 G r π ρ}{3}$

Suggest Corrections

Similar questions

Mass density of a solid sphere is ρ. Radius of the sphere is R. The gravitational field at distance r from the centre of the sphere inside it is

The density inside a solid sphere of radius a is given by $ρ$ = $ρ_{0}$ a/r where $ρ_{0}$ is the density at the surface and r denotes the distance from the centre. The gravitational field due to this sphere at a distance 2a form its centre is..

Q. The density of mass inside a solid sphere of radius

a

is given by

ρ = ρ_{0} a / r

, where

ρ_{0}

is the density at the surface and

r

denotes the distance from the centre. Find the gravitational field due to this sphere at a distance

2 a

from its centre

Q. Consider a uniform annular sphere of density

ρ

and radius

2 m

and external radius

4 m

. The gravitational field strength at a point at a distance

r = 3 m

, from the centre of the sphere is

Q. The gravitational field due to a solid sphere of radius R and mass M at a point distant R/2 from the centre of the sphere is

Join BYJU'S Learning Program

Mass density and radius of a solid sphere are ρ, R respectively. Gravitational field at an internal point which is at a distance r from the centre is.

The correct option is A 4πρGr3E(r)=GMR3r for r≤R=GR3(43πR3.ρr)=4Grπρ3

The correct option is A $\frac{4 πρGr}{3}$
$E (r) = \frac{G M}{R^{3}} r f o r r \leq R = \frac{G}{R^{3}} (\frac{4}{3} π R^{3} . ρ r) = \frac{4 G r π ρ}{3}$