Mass density of a solid sphere is ρ. Radius of the sphere is R. The gravitational field at distance r from the centre of the sphere inside it is

$\frac{4 ρ G π r}{3}$

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$\frac{4 ρ G r^{2}}{3}$

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$\frac{4 ρ G R^{3}}{3 r^{2}}$

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$\frac{ρ G R^{3}}{π r}$

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Solution

The correct option is A
$\frac{4 ρ G π r}{3}$

$E (r) = \frac{G M}{R^{3}} r f o r r \leq R = \frac{G}{R^{3}} (\frac{4}{3} π R^{3} . ρ r) = \frac{4 G r π ρ}{3}$

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Mass density of a solid sphere is ρ. Radius of the sphere is R. The gravitational field at distance r from the centre of the sphere inside it is

The correct option is A 4ρGπr3 E(r)=GMR3r for r≤R=GR3(43πR3.ρr)=4Grπρ3

The correct option is A
$\frac{4 ρ G π r}{3}$

$E (r) = \frac{G M}{R^{3}} r f o r r \leq R = \frac{G}{R^{3}} (\frac{4}{3} π R^{3} . ρ r) = \frac{4 G r π ρ}{3}$