Mass of 12-044 - 1023 atoms of hydrogen is-

The correct option is B 2 g massmolecular weight=No. of atomsN_A mass=12.044× 10^236.022× 10^23× 1 Hydrogen molecular weight = 1 g/mol ...

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Byju's Answer

Standard XII

Chemistry

Gay Lussac's Law, Avagadro's Law

Mass of 12....

Question

Mass of $12.044 \times 10^{23}$ atoms of hydrogen is:

1 g

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2 g

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3 g

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4 g

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Solution

The correct option is B $2 g$
$\frac{m a s s}{m o l e c u l a r w e i g h t} = \frac{N o . o f a t o m s}{N_{A}}$
$m a s s = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}} \times 1$ {Hydrogen molecular weight = $1 g / m o l$ }
$M a s s = 2 g$

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Mass of 12.044×1023 atoms of hydrogen is:

The correct option is B 2gmassmolecularweight=No.ofatomsNAmass=12.044×10236.022×1023×1 {Hydrogen molecular weight =1g/mol}Mass=2g

Mass of $12.044 \times 10^{23}$ atoms of hydrogen is:

The correct option is B $2 g$
$\frac{m a s s}{m o l e c u l a r w e i g h t} = \frac{N o . o f a t o m s}{N_{A}}$
$m a s s = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}} \times 1$ {Hydrogen molecular weight = $1 g / m o l$ }
$M a s s = 2 g$