1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Gay Lussac's Law, Avagadro's Law
Mass of a mol...
Question
Mass of a mole of electrons is
A
0.20
m
g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.02
m
g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.55
m
g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.00
m
g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
C
0.55
m
g
Mass of one electron is
9.1
×
10
−
25
m
g
Hence mass of 1 mol of electrons
=
6.022
×
10
23
×
9.1
×
10
−
25
m
g
=
0.55
m
g
Suggest Corrections
1
Similar questions
Q.
The average atomic mass of a mixture containing 79 mole % of
24
M
g
and remaining 21 mole % of
25
M
g
and
26
M
g
, is 24.31. The % mole of
26
M
g
in the mixture is :
Q.
Number of electrons required to deposit one mole of
M
g
2
+
ion is :
Q.
Determine the number of moles present in 0.55 mg of electrons:
Q.
The average atomic mass of a mixture containing 79 mole percent of
24
M
g
and remaining 21 mole percent of
25
M
g
and
26
M
g
,
is 24.31. Find the mole percent of
26
M
g
:
Q.
Mass of a mole of electrons is :
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Laws of Chemical Combination
CHEMISTRY
Watch in App
Explore more
Gay Lussac's Law, Avagadro's Law
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Solve
Textbooks
Question Papers
Install app