We have, coefficient of static friction, µs = 0.3
Mass, m = 10 kg
Force applied, F = 10 N
Maximum static frictional force, fmax= µs × m × g = 0.3 × 10 × 9.8
=> fmax = 29.4 N
Since applied horizontal force is less than limiting friction, the friction is same as the horizontal force which is 10 N
hope it helps