Mass of glucose in g must be present in 0.5 litre of a solution for its osmotic pressure be same as that of 8 g glucose in 1 litre is :

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Solution

The osmotic pressure is given by the expression $Π = C R T$ .
Thus, the osmotic pressure is directly proportional to the concentration.
Two solutions will have same osmotic pressure if they have same concentration.
Let w be the mass of glucose present in 0.5 L of solution.
Hence, $\frac{w}{180 g / m o l \times 0.5 L} = \frac{8 g}{180 g / m o l \times 1 L}$
$w = 4 g$
Hence, the mass of glucose present in 0.5 L of solution is 4 g.

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