Question

Mass of $H_2{C}_2{O}_4$ required to reduce 100 ml of 0.008M $KMn{O}_4$ IN acidic medium is x g and to neutralize 100 ml of 0.01M $Mg{\left(OH\right)}_2$ IS y g, then the relation between x and y is

• A. $x=y$
• B. $x=2y$
• C. $2x=y$
• D. $x=3y$

Answer 1

The correct option is A $x=y$

Mass or moles of reactant required for a reactant will be same for equal volume solutions with same normality though they are different in nature.

$n=5$ For $KMn{O}_4$ in acidic medium

$\therefore$ Normality of $KMn{O}_4=0.008\times 5=0.04N$

$n=2$ for $Mg(OH{)}_2$

$\therefore$ Normality of $Mg(OH{)}_2=0.01\times 2=0.02N$ and by the balanced reactions we can get finally $x=y$ .