Mass of hydrogen atom in 43 g of hexane $(C_{6} H_{14})$ is:

14 g

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10 g

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7 g

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6 g

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Solution

The correct option is C 7 g
Total Number of Moles = $\frac{43}{M o l . W t o f H e x a n e}$ = $\frac{43}{86}$ = 0.5 mol

Mass of Hydrogen is $0.5 \times 14 = 7 g$

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Similar questions

(C_{6} H_{14})

C_{6} H_{14} + \frac{19}{2} O_{2} \to 6 C O_{2} + 7 H_{2} O

b_{1}, b_{2}, b_{3}, . . b_{10}

g_{1}, g_{2}, g_{3}, . . . g_{10}

b_{1} = g_{1} = 1, b_{10} = g_{10} = 3

b_{4} g_{7}

(C_{6} H_{14})

C_{6} H_{14} + \frac{19}{2} O_{2} \to 6 C O_{2} + 7 H_{2} O

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