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Mole Concept & Avogadro Number

Mass of one a...

Question

Question 8
Mass of one atom of oxygen is
(a) $\frac{16}{6.023 \times 10^{23}}$ g
(b) $\frac{32}{6.023 \times 10^{23}}$ g
(c) $\frac{1}{6.023 \times 10^{23}}$ g
(d) 8u

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Solution

Mass of one atom of oxygen = $A t o m i c m a s s / N_{A}$
$= \frac{16}{6.022 \times 10^{23}} g$

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Similar questions

Q. Question 8
Mass of one atom of oxygen is
(a)

\frac{16}{6.023 \times 10^{23}}

\frac{32}{6.023 \times 10^{23}}

\frac{1}{6.023 \times 10^{23}}

Q. The number of sodium atoms in

2

moles of sodium ferrocyanide

N a_{4} [F e (C N)_{6}]

Q. One mole of oxygen corresponds to

6.023 \times 10^{23}

C O_{2}

How many moles of electrons weigh one kilogram? (Mass of electron $= 9.108 \times 10^{- 31} k g$ , Avogadro’s number $= 6.023 \times 10^{23}$ )

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Standard IX Chemistry

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