Mass of one molecule of glucose is(in grams):

180

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270

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180 \times 1.66 \times 10^{- 24}

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180 \times 1.66 \times 10^{- 23}

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Solution

The correct option is B $180 \times 1.66 \times 10^{- 24}$
Molar mass of glucose $(C_{6} H_{12} O_{6}) = 180$
Thus 1 mole of glucose has $180$ ℊ of mass.
1 mole contain $= 6.022 \times 10^{23}$ molecules
Mass of $= 6.022 \times 10^{23}$ molecule= $180$ ℊ
Therefore Mass of 1 molecule $= \frac{180}{6.022 \times 10^{23}}$

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Similar questions

180

24

1 k g

Molar mass of glucose is 180 g m o l^{- 1}

6.023 \times 10^{23}

6.023 \times 10^{24}

cos α = \frac{12}{13}, cot β = \frac{24}{7}, 90^{\circ} < α < 180^{\circ}

180^{\circ} < β < 270^{\circ}

α + β

cos α = - \frac{12}{13}, cot β = \frac{24}{7}, 90^{\circ}

α

180^{\circ}

180^{\circ}

β

270^{\circ},

α + β

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