Mass $\%$ of oxygen in Glucose is ___.

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Solution

The correct option is A

Glucose is $C_{6} H_{12} O_{6}$
Molecular mass = $(6 \times 12) + (12 \times 1) + (6 \times 16)$
$= 180 u$
Of the 180, $(16 \times 6) u$ is contributed by oxygen.
$∴$ Mass $%$ of oxygen
$= \frac{96}{180} \times 100$
$= 53.33 %$

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Mass \(\%\) of oxygen in Glucose is ___.

The correct option is A Glucose is C6H12O6 Molecular mass = (6×12)+(12×1)+(6×16) =180 u Of the 180, (16×6)u is contributed by oxygen. ∴ Mass % of oxygen =96180×100 =53.33%

The correct option is A

Glucose is $C_{6} H_{12} O_{6}$
Molecular mass = $(6 \times 12) + (12 \times 1) + (6 \times 16)$
$= 180 u$
Of the 180, $(16 \times 6) u$ is contributed by oxygen.
$∴$ Mass $%$ of oxygen
$= \frac{96}{180} \times 100$
$= 53.33 %$