$M a s s %$ of oxygen in Glucose is _____

53.33 %

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55 %

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66.33 %

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77.88 %

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Solution

The correct option is A $53.33 %$
Glucose is $C_{6} H_{1} 2 O_{6}$
Molecular mass = (6 $\times$ 12) + (12 $\times$ 1) + (6 $\times$ 16)
= 180 u
Of the 180, (16 $\times$ 6)u is contributed by oxygen.

$∴$ mass % of oxygen = $\frac{96}{180}$ $\times$ 100 = 53.33 %

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Mass% of oxygen in Glucose is _____

The correct option is A 53.33%Glucose is C6H12O6 Molecular mass = (6 × 12) + (12 × 1) + (6 × 16) = 180 u Of the 180, (16 × 6)u is contributed by oxygen. ∴ mass % of oxygen = 96180 × 100 = 53.33 %

$M a s s %$ of oxygen in Glucose is _____

The correct option is A $53.33 %$
Glucose is $C_{6} H_{1} 2 O_{6}$
Molecular mass = (6 $\times$ 12) + (12 $\times$ 1) + (6 $\times$ 16)
= 180 u
Of the 180, (16 $\times$ 6)u is contributed by oxygen.

$∴$ mass % of oxygen = $\frac{96}{180}$ $\times$ 100 = 53.33 %