$M a s s %$ of oxygen in Glucose is .

55 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

66.33 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

77.88 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

53.33 %

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $53.33 %$
Glucose is $C_{6} H_{12} O_{6}$ .
Molecular mass $= (6 \times 12) + (12 \times 1) + (6 \times 16) = 180 u$
Of the 180, $(16 \times 6) u$ is contributed by oxygen.

$∴$ mass % of oxygen $= \frac{96}{180} \times 100 = 53.33 %$

Suggest Corrections

Similar questions

Mass $\%$ of oxygen in Glucose is ___.

$M a s s %$ of oxygen in Glucose is _____

Q. During photosynthesis, the oxygen in glucose is from

A plant is provided with ideal conditions for photosynthesis and is supplied with $^{14} C O_{2}$ . When the products of the process are analyzed carefully, what would be the nature of the products?

A plant is provided with ideal conditions for photosynthesis and supplied with isotope 14 $C O_{2}$ . When the products of the process are analysed carefully, what would be the nature of products?

Join BYJU'S Learning Program

Mass% of oxygen in Glucose is .

The correct option is D 53.33%Glucose is C6H12O6. Molecular mass=(6×12)+(12×1)+(6×16)=180 u Of the 180, (16×6) u is contributed by oxygen. ∴ mass % of oxygen =96180×100=53.33%

$M a s s %$ of oxygen in Glucose is .

The correct option is D $53.33 %$
Glucose is $C_{6} H_{12} O_{6}$ .
Molecular mass $= (6 \times 12) + (12 \times 1) + (6 \times 16) = 180 u$
Of the 180, $(16 \times 6) u$ is contributed by oxygen.

$∴$ mass % of oxygen $= \frac{96}{180} \times 100 = 53.33 %$