Mass pulley system is shown in figure. The string is massless. One end of the string is pulled by the force F=2mg. The acceleration of the block will be (mass of pulley is m).
A
g/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D3g Force is applied on the 2nd rope is 2mg so the tension developed is 2mg.
So, the net tension on 1st rope will be 2T that is 2×mg=4mg