Masses of copper wires are in ratio 1:3:5 and lengths of ratio 5:3:1 . Whats the ratio of their electrical resistances ?
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Solution
mass ratio of 3 wires 1 : 3 : 5
lengths are in ratio 5 : 3: 1
V = A * L
V = pi*r^2 * L
density = d
m = V*d
m = A*L * d
A = m/(L *d)
R = p*L/A
p is constant for all copper so now we just have to find the ratio of L to area since d = density of copper it is constant too .. so the only variables are
A varies m/L
R varies L/A
R varies by L/ (m/L)
R varies by L*L/m
R varies by L^2/m
first wire
R1 = 5^2/1 = 25
R2 = 3^2/3 = 3
R3 = 1^2/5 = 1/5
the resistance vary by
25 : 3: 1/5
or
125 : 15 : 1
I multiplied by 5 through the whole thing (HOPE YOU LIKED MY ANSWER 😊😊😊)