Masses of three wires of the same metal are in the ratio 1:2:3 and their lengths in the ratio 3:2:1. Electrical resistances of these wires will be in the ratio
A
1:2:3
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B
3:2:1
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C
1:6:27
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D
27:6:1
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Solution
The correct option is C27:6:1 Here the ratio of masses of the wires is 1:2:3. So, m1=k,m2=2k and m3=3k, where k is the proportionality constant. And the ratio of there lengths is 3:2:1. So, l1=3s,l2=2s,l3=s, where s is also a proportionality constant.