Question

Match Column $I$ (reactant) with the amount in Column $II$.

Answer 1

(A) $\underset{1mol}{C{H}_{3}COOH}+NaOH⟶C{H}_{3}COONa+H_{2}O$. 1 mole or 1 equivalent or $40g$ of $NaOH$ used to react completely with $C{H}_{3}COOH$
(B) $\underset{84g}{MgC{O}_3}\stackrel{\Delta }{\to }MgO+C{O}_2$Residue formed is 1 mole or $40g$
(C) $\underset{2mol}{2S{O}_2}+\underset{64g}{O_2}⟶2S{O}_3$. 1 mole or 4 equivalents of the reactant in excess under standard conditions which occupies a volume of $22.4L$ at STP.
(D) $2H_2+O_2⟶2H_{2}O$. 1 mole or 4 equivalents of $O_2$ is used to form 36 g $H_{2}O$ which occupies a volume of 22.4 L at STP.
(E) $N_2{H}_4+O_2⟶N_2+2H_{2}O$. 1 mole or 4 equivalents of $N_2$ formed from $32g$ each reactant and it occupies a volume of 22.4 L at STP.