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Question

Match Column I (reactant) with the amount in Column II.

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Solution

(A) CH3COOH1mol+NaOHCH3COONa+H2O. 1 mole or 1 equivalent or 40g of NaOH used to react completely with CH3COOH
(B) MgCO384gΔMgO+CO2Residue formed is 1 mole or 40g
(C) 2SO22mol+O264g2SO3. 1 mole or 4 equivalents of the reactant in excess under standard conditions which occupies a volume of 22.4L at STP.
(D) 2H2+O22H2O. 1 mole or 4 equivalents of O2 is used to form 36 g H2O which occupies a volume of 22.4 L at STP.
(E) N2H4+O2N2+2H2O. 1 mole or 4 equivalents of N2 formed from 32g each reactant and it occupies a volume of 22.4 L at STP.

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