Question

Match column I with column II and select the correct answer using the codes given below the columns.

Column I lists the metal ion and Column II lists the Magnetic moment (BM) :

Answer 1

The number of unpaired electron for $C{r}^{3+},F{e}^{2+},N{i}^{2+}andM{n}^{2+}$ is 3, 4, 2 and 5 respectively.

Magnetic moment calculated by $\sqrt{n(n+2)}$.

Magnetic moment of $C{r}^{3+}$= $\sqrt{3(3+2)}$ = $\sqrt{15}$.

Magnetic moment of $F{e}^{2+}$ = $\sqrt{4(4+2)}$ = $\sqrt{24}$.

Magnetic moment of $N{i}^{2+}$ = $\sqrt{2(2+2)}$ = $\sqrt{8}$.

Magnetic moment of $M{n}^{2+}$ = $\sqrt{5(5+2)}$ = $\sqrt{35}$.