Question

Match column-I with column-II and select the correct answer using the codes given below.
$\begin{array}{cccc}& \text{Column - I}& & \text{Column - II}\\ \text{A}& \text{ABO blood groups}& \text{I.}& \text{Dihybrid cross}\\ \text{B}& \text{Law of segregation}& \text{II.}& \text{Monohybrid cross}\\ \text{C}& \text{Law of Independent assortment}& \text{III.}& \text{Base pairs substitution}\\ \text{D}& \text{Gene mutation}& \text{IV.}& \text{Multiple allelism}\end{array}$

• A. A – IV; B – II; C – I; D – III
• B. A – II; B – III; C – IV; D – I
• C. A – II; B – I; C – IV; D – III
• D. A – IV; B – I; C – II; D – III

Answer 1

The correct option is A A – IV; B – II; C – I; D – III

ABO blood group is an example of multiple allelisms because of presence of more than two alleles (IA, IB and i) of a gene determining the blood groups.

Law of segregation can be explained with the help of monohybrid cross.

Law of independent assortment can be explained with the help of dihybrid cross. Law of independent assortment states that allele pairs, which are independent of one another, separate independently during the formation of gametes.

Gene mutation is a sudden heritable change in the sequence of the DNA.