Match column I with column II and select the correct option from the given codes.
Column - I Column - II
(a)
(b)
(c)
(d) Squamous epithelium
Columnar epithelium
Cuboidal epithelium
Ciliated epithelium (i)
(ii)
(iii)
(iv) Gall bladder
Oviduct
Heart
Thyroid gland

a - (iii), b - (i), c - (iv), d - (ii)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a - (iii), b - (iv), c - (i), d - (ii)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a - (iv), b - (i), c - (iii), d - (ii)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a - (ii), b - (iv), c - (i), d - (iii)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A a - (iii), b - (i), c - (iv), d - (ii)
The heart consists of simple squamous epithelium.
Gallbladder consists of columnar epithelium which is necessary for bearing goblet cells.
Thyroid gland consists of cuboidal epithelium within the thyroid follicles.
Oviduct consists of ciliated epithelium for the motion of matter through the duct.
Hence, the correct option is A.

Suggest Corrections

Similar questions

Q. Match Column-I with Column-II and select the correct option from the codes given below.

\begin{matrix} Column-I & Column-II A . & Vessels & I . & Cells are living with thin cellulosic cell walls B . & Tracheids & II . & Cells possess highly thickened walls with obliterated central lumen C . & Xylem fibres & III . & Interconnected through perforations in their common walls D . & Xylem parenchyma & IV . & Tube-like with thick, lignified walls and tapering ends \end{matrix}

Match the column I with column II and select the correct option given.

$\begin{matrix} Column I & Column II A . & Allen's rule & (i) & Sigmoid curve due to limited resources B . & Verhulst - Pearl logistic growth & (i i) & Breed only once in their life - time C . & Extnction of Abingdon tortoise & (i i i) & Competition for same resources D . & Pacific Salmon fish and bamboo & (i v) & Colder climates mammals \end{matrix}$

Q. Match column-I with column-II and select the correct answer using the codes given below.

\begin{matrix} Column - I & Column - II A & ABO blood groups & I. & Dihybrid cross B & Law of segregation & II. & Monohybrid cross C & Law of Independent assortment & III. & Base pairs substitution D & Gene mutation & IV. & Multiple allelism \end{matrix}

Q. Match the compounds given in column I with the hybridisation and shape given in column II and mark the correct option.

\begin{matrix} C o l u m n I & C o l u m n I I (A) & X e F_{6} & (i) & d i s t o r t e d o c t a h e d r a l (B) & X e O_{3} & (i i) & s q u a r e p l a n a r (C) & X e O F_{4} & (i i i) & p y r a m i d a l (D) & X e F_{4} & (i v) & S q u a r e p y r a m i d a l \end{matrix}

Q. Match Column-I with Column-II and select the correct option from the codes given below.

\begin{matrix} C o l u m n - I & C o l u m n - I I A . & V - s h a p e d a t a n a p h a s e & i) & A c r o c e n t r i c c h r o m o s o m e B . & L - s h a p e d a t a n a p h a s e & i i) & M e t a c e n t r i c c h r o m o s o m e C . & J - s h a p e d a t a n a p h a s e & i i i) & T e l o c e n t r i c c h r o m o s o m e D . & I - s h a p e d a t a n a p h a s e & i v) & S u b - m e t a c e n t r i c c h r o m o s o m e \end{matrix}

Join BYJU'S Learning Program

	Column - I		Column - II
(a) (b) (c) (d)	Squamous epithelium Columnar epithelium Cuboidal epithelium Ciliated epithelium	(i) (ii) (iii) (iv)	Gall bladder Oviduct Heart Thyroid gland

Match column I with column II and select the correct option from the given codes.Column - IColumn - II(a)(b)(c)(d)Squamous epitheliumColumnar epitheliumCuboidal epitheliumCiliated epithelium(i)(ii)(iii)(iv)Gall bladderOviductHeartThyroid gland

Match column I with column II and select the correct option from the given codes.
Column - I Column - II
(a)
(b)
(c)
(d) Squamous epithelium
Columnar epithelium
Cuboidal epithelium
Ciliated epithelium (i)
(ii)
(iii)
(iv) Gall bladder
Oviduct
Heart
Thyroid gland