Question

Match column I with column II and select the correct option from the given codes.

Sr.No	Column I	Sr.No	Column II
A	Tetrose sugar	(i)	Galactose
B.	Pentose sugar	(ii)	Maltose
C.	Hexose sugar	(iii)	Erythrose
D.	Disaccharide	(iv)	Ribose
			Sedoheptulose

• A. A-(v);B-(iv);C-(iii);D-(i);(ii)
• B. A-(iii);B-(iv);C-(v);(ii)
• C. A-(iii);B-(iv);C-(i);D-(ii)
• D. A-(i),(ii);B-(iv);C-(iii);D-(v)

Answer 1

Answer: (C)

A-(iii);B-(iv);C-(i);D-(ii)

On the basis of the number of carbon molecule present in the monosaccharides they are divided into tetrose sugar that means four Carbon; for example, erythrose, pentose sugar that has 5 carbon that is ribose and it are found in the nucleus acid. Hexose sugar which is galactose, and glucose.

Disaccharides are formed when two monosaccharides units join together for example of a disaccharide is maltose.

So, the correct option is 'A-(iii);B-(iv);C-(i);D-(ii)'