Question

Match column I with column II:
$\begin{array}{cc}\text{Column - I}& \text{Column - II}\\ \text{i.}Cr(OH{)}_3+H_2{O}_2\text{in basic medium}& \text{p.}CO+H_2\\ \text{ii. Acidic}KMn{O}_4+H_2{O}_2& \text{q.}N{H}_3\\ \text{iii.}C{a}_3{N}_2+H_{2}O& \text{r. Water-gas}\\ \text{iv. Red-hot coke + steam (at 1273 K, Ni catalyst)}& \text{s. Yellow solution}\\ & \text{t.}Ca(OH{)}_2\\ & \text{u. Solution decolourised}\end{array}$

• A. $\text{(i-s), (ii-u), (iii-q, t), (iv-p, r)}$
• B. $\text{(i-r), (ii-t), (iii-q,u), (iv-p, s)}$
• C. $\text{(i-u), (ii-s), (iii-q, t), (iv-p, r)}$
• D. $\text{(i-u), (ii-s), (iii-q, t), (iv-p, r)}$

Answer 1

The correct option is A $\text{(i-s), (ii-u), (iii-q, t), (iv-p, r)}$

$\text{i.}Cr(OH{)}_3+H_2{O}_2\rightleftharpoons \underset{yellowsolution}{Cr{O}_4^{2-}}+H_{2}O$

$\text{ii.}\underset{\left(violetcolour\right)}{2KMn{O}_4}+5H_2{O}_2+3H_{2}S{O}_4\to 2MnS{O}_4+5O_2+K_{2}S{O}_4+8H_{2}O$
The resultant solution is colourless, i.e., the solution gets decolourised.

$\text{iii.}C{a}_3{N}_2+6H_{2}O\to 3Ca(OH{)}_2+2N{H}_3\uparrow$

$\text{iv. Red hot coke + steam}\stackrel{1273K}{\to }\text{Watergas}$
$C+H_{2}O\left(g\right)\stackrel{1273K}{\rightleftharpoons }CO+H_2\left(g\right)$