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Question

Match Column-I with Column-II:
Column-IColumn-IIa. [Ni(CN)4]2p. d2sp3b.[Ni(CO)4]q. sp3d2c. [Co(en)3]3+r. dsp2d. [Co(Br)3Cl3]3s. sp3t. Inner orbital complex u. Outer orbital complex

A
(ar,t),(bs,u)
(cp,t),(dp,t)
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B
(as,t),(br,u)
(cp,t),(dp,t)
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C
(ar,t),(bs,u)
(cq,t),(dp,t)
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D
(as,t),(bs,u)
(cq,u),(dq,u)
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Solution

The correct option is A (ar,t),(bs,u)
(cp,t),(dp,t)
When the complex formed involves the inner `'(n-1)d'` orbital for hybridisation `(d^2sp^3)`, the complex is called inner orbital complex. They are also called as low spin complex.

When the complex formed involves the outer `'nd'` orbital for hybridisation `(sp^3d^2)`, the complex is called outer orbital complex. They are also called as high spin complex.

[Ni(CN)4]2
The ligand is CN
It is a strong field ligand for Ni2+
Ni2+3d84s04p04d0
Pairing of electron happens due to the presence of a strong field ligand. Thus, the hybridization is dsp2 and the geometry is square plannar and it forms an inner orbital complex.

[Ni(CO)4]
The ligand is CO
It is a strong field ligand for Ni
Ni3d84s24p04d0
In the presence of a strong field ligand, the electrons in `s`-orbitals gets shifted to the `d`-orbital and thus the hybridisation is sp3 and it forms an outer orbital complex.

[Co(en)3]3+
The ligand is Ethylene diammine
It is a strong field ligand for Co3+
Co3+3d64s04p04d0
Pairing of electrons takes place because of the presence of a strong field ligand. Thus the hybridisation will be it d2sp3 and it forms an inner orbital complex.

[Co(Br)3(Cl)3]3
The ligand is Cl and Br
They are strong field ligands for Co3+
Co3+3d64s04p04d0
Pairing of electrons takes place due to the presence of strong field ligands. Thus the hybridisation will be d2sp3 and it forms an inner orbital complex .

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