Match Column I with Column II in the following:

$\begin{matrix} C o l u m n I & C o l u m n I I 1. & T h e d i f f e r e n c e o f 3 a n d a n u m b e r & (a) & 4 - 2 x s q u a r e d 2. & 5 l e s s t h a n t w i c e a n u m b e r s q u a r e d & (b) & n^{2} - 3 3. & F i v e m i n u s t w i c e t h e s q u a r e o f a & (c) & 2 n^{2} - 5 n u m b e r 4. & F o u r m i n u s a n u m b e r m u l t i p l i e d b y 2 & (d) & 5 - 2 n^{2} 5. & S e v e n t i m e s t h e s u m o f a n u m b e r a n d 1 & (e) & 3 - n^{2} 6. & A n u m b e r s q u a r e d p l u s 6 & (f) & 2 (n + 6) 7. & 2 t i m e s t h e s u m o f a n u m b e r a n d 6 & (g) & 7 (n + 1) 8. & T h r e e l e s s t h a n t h e s q u a r e o f a n u m b e r & (h) & n^{2} + 6 \end{matrix}$

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Solution

$1 \to$ (e) Let the number be n.
So, according to the statements,
we can write the equation = 3 $- n^{2}$
$2 \to$ (c) Let the number be n.
So, the equation is $2 n^{2} - 5.$
$3 \to$ (d) Let the number be n.
So, the equation is $5 - 2 n^{2} .$
$4 \to$ (a) Let the number be x.
So, the equation is 4-2x.
$5 \to$ (g) Let the number be n.
So, the equation is 7(n+1).
$6 \to$ (h) Let the number be n.
So, the equation is $n^{2} + 6.$
$7 \to$ (f) Let the number be n.
So, the equation is 2(n+6).
$8 \to$ (b) Let the number be n.
So, the equation is $n^{2} - 3.$

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