wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Match Column I with Column II, where column II represents ‘I’.
Column IColumn IIa. K4[Fe(CN)6]p. 1b. Fe2(SO4)3q. 1+4αc. C6H12O6r. 1+αd. BaCl2s. Greater than 1t. Less than 1

A
(a - q ; b - s; c - p; d - s)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(a - q, s;b - q, s;c - p; d - s)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(a - q, s;b - q, s;c - p, s; d - s)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(a - q, s;b - q, s;c - p,s; d - p,s)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (a - q, s;b - q, s;c - p; d - s)
(a) K4[Fe(CN)6 4K++ [Fe(CN)6]4
1
1 -α 4α α
Total = 1 + 4α >1

(b) Fe2(SO4)3 2Fe3++ 3(SO4)2
1
1 -α 2α 3α
Total = 1 + 4α >1

(c) Glucose does not dissociate.

(d) BaCl2 Ba2++ 2Cl
1
1 -α α 2α
Total = 1 + 2α >1


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Potassium Hydroxide
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon