Question

Match column I with II in which the formula for estimation of an element is given and mark the appropriate choice.

• A. $\left(A\right)\to \left(v\right),\left(B\right)\to \left(ii\right),\left(C\right)\to \left(iv\right),\left(D\right)\stackrel{}{\to }\left(i\right)$ $\left(E\right)\to \left(iii\right)$
• B. $\left(A\right)\to \left(v\right),\left(B\right)\to \left(iv\right),\left(C\right)\to \left(i\right),\left(D\right)\to \left(iii\right),\left(E\right)\to \left(ii\right)$
• C. $\left(A\right)\to \left(v\right),\left(B\right)\to \left(iv\right),\left(C\right)\to \left(ii\right),\left(D\right)\to \left(i\right)$ $\left(E\right)\to \left(iii\right)$
• D. $\left(A\right)\to \left(iv\right),\left(B\right)\to \left(iii\right),\left(C\right)\to \left(i\right),\left(D\right)\to \left(ii\right),\left(E\right)\to \left(v\right)$

Answer 1

The correct option is B $\left(A\right)\to \left(v\right),\left(B\right)\to \left(iv\right),\left(C\right)\to \left(i\right),\left(D\right)\to \left(iii\right),\left(E\right)\to \left(ii\right)$

• $\%$ of $C=\frac{12}{44}\times \frac{w_1}{w}\times 100$

$(w_1=$ weight of ${CO}_2,w=$ weight of organic compound)

• $\%$ of $N=\frac{28}{22400}\times \frac{V}{w}\times 100$

$(V=$ volume of $N_2$ at STP, $w=$ weight of organic compound)

• $\%$ of $Br=\frac{80}{188}\times \frac{w_1}{w}\times 100(w_1=$ weight of $AgBr)$

• $\%$ of $S=\frac{32}{233}\times \frac{w_1}{w}\times 100(w_1=$ weight of ${BaSO}_4)$

• $\%$ of $P=\frac{62}{222}\times \frac{w_1}{w}\times 100(w_1=weight$ of ${Mg}_2{P}_2{O}_7)$

Hence option (B) is correct.