Question

Match correctly

Answer 1

$A)$ Each angle of an equilateral triangle is $60°$.

$B)$ Measure of the base angle is double the vertical angle.

Let vertical angle be $x$.

Then base angle $=2x$,

So, $x+2x+2x=180°$

$⟹x=36°$

$C)$ Sum of exterior angles $=180-B+180-C$

$=360-(180-A)$

$=180+A$

So, it is greater then $two$ right angles.

$D)$ Point of intersection of the angle bisectors of $a$ $△$ is incentre.