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Question

Match each coordination compound in List - I with an appropriate pair of characteristics from List - II and select the correct answer using the code given below the lists.
{en = H2NCH2CH2NH2 (atomic numbers: Ti=22;Cr=24;Co=27;Pt=78}
List IList II(P) [Cr(NH3)4Cl2]Cl(1) Paramagnetic and exhibitsionization isomerism(Q) [Ti(H2O)5Cl](NO3)2(2) Diamagnetic and exhibitscis−trans isomerism(R) [Pt(en)(NH3)Cl]NO3(3) Paramagnetic and exhibitscis−trans isomerism(S) [Co(NH3)4(NO3)2]NO3(4) Diamagnetic and exhibitsinonization isomerism

A
R - 3, S - 1
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B
R - 4, S - 2
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C
R - 3, S - 4
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D
R - 4, S - 1
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Solution

The correct option is B R - 4, S - 2
List IList II(P) [CrIII(NH3)4Cl2]Cl(1) Complex given in (P) is paramagnetic(3 unpaired electrons)and shows geometrical isomerism(cis and trans) (does not show ionization isomerism)(Q) [TiIII(H2O)5Cl](NO3)2](2) Complex given in (Q) is paramagnetic(1 unpaired electron)and shows ionization isomerism(R) [PtII(en)(NH3)Cl]NO3(3) Complex given in (R) is diamagnetic(0 unpaired electron)and shows ionization isomerism(S) [CoIII(NH3)4(NO3)2]NO3(4) Complex given in (S) is diamagnetic(0 unpaired electron)and does not show ionization isomerism(shows geometrical isomerism)

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