Question

Match each figure to its area.

• A. $50c{m}^2$
• B. $6c{m}^2$
• C. $9c{m}^2$

Answer 1

Case(1):
Since triaangle is a right angled triangle
So,
ar(ABC) = $\frac{1}{2}\times base\times height$
= $\frac{1}{2}\times b\times h$
=$\frac{1}{2}\times 4\times 3$
= 6$c{m}^2$

Case(2):
So, ABCD is a rectangle
ar (ABCD) = $length\times breadth$
= $l\times b$
= $10\times 5$
= 50$c{m}^2$

Case(2):
Since, ABCD is a square
So,
ar ( ABCD) = $(side{)}^2$
= $(s{)}^2$
= $(3{)}^2$
= 9 $c{m}^2$