Question

Match for the correct value of x

• A. 20
• B. 4
• C. 3
• D. 5

Answer 1

Case(1):
x+5=8
Subtracting 5 from both sides of the equation
x+5-5=8-5
x= 3
Case(2):
x-3=2
Adding 3 to both sides of the equations
x-3+3=2+3
x=5
Case(3):
$\frac{x}{4}=5$
Multiplying by 4 on both sides of the equation
$\frac{x}{4}\times 4=5\times 4$
x= 20
Case(4):
$6x=24$
Dividing by 6 on both sides of the equations
$\frac{6x}{6}=\frac{24}{6}$
$x=\frac{24}{6}$
x= 4