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Byju's Answer

Standard XII

Chemistry

Stoichiometry

Match List-1 ...

Question

Match List-1 with List-2.

List -1 List-2
A) Aq. Solution of NaCl 1)Acidic buffer
B) Aq. Solution of $C H_{3} C O O N a$ 2)Acidic solution
C) Aq. Solution of $N H_{4} C l$ 3) Basic solution
D) Aq. Solution of $C H_{3} C O O H$ along with $C H_{3} C O O N a$ 4)Neutral solution

A - 1; B - 2; C - 3; D - 4

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A - 4; B - 3; C - 2; D - 1

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A - 3; B - 4; C - 2; D - 1

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A - 4; B - 3; C - 1; C - 2

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Solution

The correct option is B $A - 4; B - 3; C - 2; D - 1$
$N a C l$ is a salt of strong acid $H C l$ and strong base $N a O H$ . It does not undergo hydrolysis in water. Hence its aqueous solution is neutral.

Sodium acetate is a salt of strong base sodium hydroxide and weak acid acetic acid. Its solution is basic in nature.

Ammonium chloride is the salt of strong acid $H C l$ and weak base ammonium hydroxide. Its solution is acidic in nature.

A mixture of acetic acid and sodium acetate is an acidic buffer. Its aqueous solution is acidic in nature.

Thus, A-4 ; B-3; C-2; D-1

Hence, the correct option is $B$

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Similar questions

Match List-1 with List-2.

List -1 List-2
A)

C H_{3} C O O N a + C H_{3} C O O H

1)Acidic due to cationic hydrolysis
B)

N H_{4} C l + N H_{4} O H

2)Basic due to anionic hydrolysis
C) aqueous

A l C l_{3}

3) Basic buffer solution
D) aqueous

N a_{2} C O_{3}

4)Acidic buffer solution

Match the entries in Column - I with those in Column - II
$\begin{matrix} Column - I & Column - II a. & A chalk water & 1 & A gaseous mixture & mixture b. & A glucose & 2 & A heterogeneous solution & solid-liquid mixture c. & Carbonated & 3 & A homogeneous water & solid-liquid mixture d. & Air & 4. & A gas-liquid mixture \end{matrix}$

Q. Consider the four processes

A, B, C, D

shown in the graph given below

List I shows process & List II gives value of index

^{'} n^{'}

for the equation

P V^{n} = const

Match List I with list II.

\begin{matrix} List I & List II A . & A & 1. & 0 B & B & 2 & 1 C & C & 3. & 1.4 D & D & 4. & \infty \end{matrix}

Q. Match the elements of the list I, which contains inequalities, with the elements of list II, which has solution sets.

List-I (Inequality)	List-II (Solution set)
A) $x^{2} - 4 x + 3 > 0$	1) $(3, 4)$
B) $x^{2} - 5 x + 6 \leq 0$	2) $(- 1, 1) \cup (2, 4)$
C) $x^{2} + 6 x - 27 > 0, - x^{2} + 3 x + 4 > 0$	3) $(- \infty, 1) \cup (3, \infty)$
D) $x^{2} - 3 x - 4 < 0, x^{2} - 3 x + 2 > 0$	4) $[3, 4]$
	5) $[2, 3]$

Then the correct order for A B C D, is

Balance the following redox reactions by ion-electron method:

(a) (aq) + I^– (aq) → MnO₂ (s) + I₂(s) (in basic medium)

(b) (aq) + SO₂ (g) → Mn²⁺ (aq) + (aq) (in acidic solution)

(d) + SO₂(g) → Cr³⁺ (aq) + (aq) (in acidic solution)

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List -1	List-2
A) Aq. Solution of NaCl	1)Acidic buffer
B) Aq. Solution of $C H_{3} C O O N a$	2)Acidic solution
C) Aq. Solution of $N H_{4} C l$	3) Basic solution
D) Aq. Solution of $C H_{3} C O O H$ along with $C H_{3} C O O N a$	4)Neutral solution

Match List-1 with List-2. List -1 List-2 A) Aq. Solution of NaCl 1)Acidic buffer B) Aq. Solution of CH3COONa 2)Acidic solution C) Aq. Solution of NH4Cl 3) Basic solution D) Aq. Solution of CH3COOH along with CH3COONa 4)Neutral solution

Match List-1 with List-2.

List -1 List-2
A) Aq. Solution of NaCl 1)Acidic buffer
B) Aq. Solution of $C H_{3} C O O N a$ 2)Acidic solution
C) Aq. Solution of $N H_{4} C l$ 3) Basic solution
D) Aq. Solution of $C H_{3} C O O H$ along with $C H_{3} C O O N a$ 4)Neutral solution